Bash Script to create a file for each unique permission in a listing/find command and printing each directory/file path instance of that permission

Question

I'm trying to create a bash script that will be able to perform a find command to get the permissions and full path of every file/directory in a directory tree and create a file for each unique permission and printing each full file path to that permissions file. Then in the future I could read these files and use them to permissions to the way they were when I ran the script.

For instance:

drwxrwxrwx /home/user/testDirectory  
-rwxrwxrwx /home/user/testDirectory/testFile  
drwxr-xr-x /home/user/testDirectory/directory2  
-rwxr-xr-x /home/user/testDirectory/directory2/test2

The above would create 2 files (e.g. 777.txt and 755.txt) that would each have 2 of the lines.

I am struggling with the logic to create a file for each unique permission and then send the full file path.

What I have so far (I doubt the array is necessary, but I have played with sorting the array by permission which I can do with -k 1.2 on the sort command to ignore the d flag):

declare -a PERMS

i=0

while read line
do
     PERMS[$i]="$line"
     (( i++ ))
done < <( find /opt/sas94 -printf ""%M/" "%p/"\n")

Can we assume that none of your directory or file names will contain a newline character? — Chris Davies
– Chris Davies, Commented Jun 6, 2019 at 18:56
Since directory and file names can easily contain one or more spaces I'd suggest you put the permissions number/string as the first item and the path name as the remainder of the line. — Chris Davies
– Chris Davies, Commented Jun 6, 2019 at 18:59
Yes no newline characters. The permissions are the first thing printed by the find command. Looking at my initial post I realize the format screwed up for the example output of the file command. But each line starts with a permission and then the full path. One combo per line. — Varathiel
– Varathiel, Commented Jun 6, 2019 at 19:06
What is going on with your quotes “-printf ""%M/" "%p/"\n"”? — ctrl-alt-delor
– ctrl-alt-delor, Commented Jun 6, 2019 at 19:13
Apparently, the ones around the %M and %p are unnecessary. It works both as ""%M/" "%p/"\n" and "%M/ %p/\n". — Varathiel
– Varathiel, Commented Jun 6, 2019 at 19:29

Freddy · Accepted Answer · 2019-06-06 20:28:12Z

3

Try this:

#!/bin/bash

while read file; do
        stat -c '%A %n' "$file" >> $(stat -c '%a' "$file").txt
done < <(find "$1")

Usage:

./script.sh /path/to/directory

the first stat -c '%A %n' "$file" prints the permissions and path to the file, e.g. -rw-rw-rw- /foo/bar
the second stat -c '%a' "$file" prints the permissions in octal form, e.g. 666

The output of the first stat is appended to the filename created by the second stat with suffix .txt.

answered Jun 6, 2019 at 20:28

Freddy

26.3k1 gold badge27 silver badges64 bronze badges

Thank you! This works great.

Varathiel
– Varathiel

2019-06-07 15:01:49 +00:00
Commented Jun 7, 2019 at 15:01

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