Can i use string in C++ which support embedded NULL character?
My issue is: Constructing string with embedded NULL and hence sent it to C++ DLL as an array of bytes.
string inputStr("he\0llo", 6);
int byteLength = 6;
BYTE *inputByte = (BYTE*)(char*)inputStr.c_str();
ApplyArabicMapping(inputByte , byteLength);
Yes, std::string supports storing NULL characters because it is not NULL-terminated. You can create one in many ways:
string str("he\0llo", 6);
str.append(1, '\0');
str.push_back('\0');
const char[] cstr = "hell\0o";
string str2(cstr, cstr + sizeof(cstr) - 1); // - 1 for the NULL
std::vector<char> is functionally almost the same and has the advantage of making clear that you might find chars you don't expect in the container.
std::string, while using std::vector<unsigned char> for binary data.
std::string. I believe it is better to learn not to assume that and get over with. The difference between std::string and std::vector<char> is that the former indicates that you are storing text not just small numbers, and that it offers a much richer (too rich in places) for processing.(BYTE), could that be BYTE*?)
std::vector<char> also says you're storing characters; I (and many others) would use std::vector<signed char> for small integers. Still, std::string does seem to suggest some sort of actual text, whereas std::vector<char> suggests just a lot of characters. I'd use std::string for text unless there were particular reasons not to, even though in practice, I never use anything that wouldn't work just as well with std::vector<char>.You can use counted strings, where the character buffer is stored alongside with its "content length"; this allows you to embed any character. std::string, for example, is a kind of counted string.
Obviously, you cannot pass such a string to a function that expects a classic C-string, because it will see the first null it encounters as the string terminator.
'\0'character to know that it ends. furthermore, if you use the string.c_str() method, you get an array of characters with the'\0'character at the end.vector<char>instead. Why do you need this?string(which in C++ would bestd::stringunless otherwise said), but rather in the use of a different interface. That is, the question lacks the most important bits of information, that are only sprinkled in comments.