I need to define the type of passed variable as an generic object, how?
Tried:
public function set($service = null, (object) $instance) {
[..]
}
Can stdClass help? How?
Thanks!
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3 Answers
Nope, in php all classes aren't derive from the common ancestor.
So doubtfully you can use current php's implementation to state "object of any class"
3 Comments
Gabriel Santos
So, solution only inside the function with
is_object?
zerkms
@Gabriel Santos: yes. Or, if you could, just create interface and
implement it in each required classGabriel Santos
No, interface in this case is so ugly. Thanks for help!
No, the object has to be some class. You can give the any class name as object's type
public function set($service = null, ClassName $instance) {
//now the instance HAS to be the object of the class
}
Or a basic trick would be to create a basic class yourself
Class GenericObject {}
$myobj = new GenericObject();
$myobj -> myCustomVar = 'my custom var';
//Now send it
public function set($service = null, GenericObject $instance) {
[...]
}
1 Comment
Gabriel Santos
Thanks for samples, but, it is for a Service Locator, which will not work correctly with this approach.
Gabriel,
if what you want to do is check if the variable is an object, you could do this:
public function set($service = null, $instance) {
if (!is_object($instance)) return null; //or whatever
[..]
}
What are you trying to prevent with that? With your declaration, you would get an exception if the variable is not an object (it will not cast it).
4 Comments
Gabriel Santos
I have a "exception catcher".
Gabriel Santos
I know about
is_object inside set function, but I thought about casts.zerkms
@Gabriel Santos: to be precise it has nothing to do with "casts" in php, it is called "type hinting"
Gabriel Santos
function set($service = null, (object) $instance) casting $instance as Object