PHP echo function is not working as expected

Question

I am new to PHP and WordPress and currently in learning phase.I am trying to append the host name of in my WordPress site URL so that i can change the host name at any time and here is waht i am trying to do

<?php
   $site="siteurl";
   $home="home";
?>

this is what i am trying to do in my php page

<link rel="stylesheet" href ="<?php echo get_cdn($site_cdn); ?>/wp-
content/themes/abc/scripts/fancybox/jquery.fancybox-1.3.4.css" 
type="text/css" />

here is my get_cdn() function

function get_cdn($cdn_name){
 if ($cdn_name="home" || $cdn_name="siteurl"){
     return "http://id.cloudfront.net";
  }
  else{
     return $cdn_name;
  }
}

so what i am trying to do is if the pass in value to the function is either home or siteurl, it will return the URL of amazon cdn server so as per my understanding the above script should be like

<link rel="stylesheet" href ="http://id.cloudfront.net/wp-
    content/themes/abc/scripts/fancybox/jquery.fancybox-1.3.4.css" 
    type="text/css" />

but this is coming as

http://localhost/wordpress/id.cloudfront.net/wp-content/themes/abc/scripts/fancybox/jquery.fancybox-1.3.4.css

i am not sure why this is happening and any help/pointer in this regard will be helpful

Gustav Westling · Accepted Answer · 2012-04-15 17:10:03Z

4

if($cdn_name == "home" || $cdn_name == "siteurl"){

To match two values with eachother, use $a == $b. Two "=" that is. In PHP, === will also match the datatype.

answered Apr 15, 2012 at 17:10

Gustav Westling

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Comments

ahmetunal · Accepted Answer · 2012-04-15 17:10:56Z

1

what is $site_cdn parameter you are sending, check that first.

It looks like you are sending an empty parameter, so your get_cdn function returns an empty string, and your src attribute is like

src="/wp-content/themes/abc/scripts/fancybox/jquery.fancybox-1.3.4.css"

and since you didn't specify any host, html fetches the css from your localhost

answered Apr 15, 2012 at 17:10

ahmetunal

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