Why can't I replace the str method of a Python object with another function?

Question

Here is the code:

class Dummy(object):
    def __init__(self, v):
        self.ticker = v


def main():
        def _assign_custom_str(x):
            def _show_ticker(t):                
                return t.ticker
            x.__str__ = _show_ticker
            x.__repr__ = _show_ticker
            return x


    a = [Dummy(1), Dummy(2)]

    a1 = [_assign_custom_str(t) for t in a]
    print a1[1]
    # print a1[1].__str__ # test to if orig __str__ is replaced

I was hoping to see the output like this

However, instead I see the standard representation:

<__main__.Dummy object at 0x01237730>

Why?

Note that this does work with old-style classes (not extending object). See my question for the difference: stackoverflow.com/questions/16062293/… — BoppreH
– BoppreH, Commented Apr 17, 2013 at 14:34

agf · Accepted Answer · 2021-06-11 03:28:51Z

17

Magic methods are only guaranteed to work if they're defined on the type rather than on the object.

For example:

def _assign_custom_str(x):
        def _show_ticker(self):                
            return self.ticker
        x.__class__.__str__ = _show_ticker
        x.__class__.__repr__ = _show_ticker
        return x

But note that will affect all Dummy objects, not just the one you're using to access the class.

edited Jun 11, 2021 at 3:28

answered May 8, 2012 at 5:31

agf

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2 Comments

dshanahan Over a year ago

updated link

agf Over a year ago

@dshanahan Thanks, fixed in the answer. In the future please suggest an edit rather than leaving a comment.

HYRY · Accepted Answer · 2012-05-08 05:43:34Z

1

if you want to custmize __str__ for every instance, you can call another method _str in __str__, and custmize _str:

class Dummy(object):
    def __init__(self, v):
        self.ticker = v

    def __str__(self):
        return self._str()

    def _str(self):
        return super(Dummy, self).__str__()

def main():
    a1 = Dummy(1)
    a2 = Dummy(2)

    a1._str = lambda self=a1:"a1: %d" % self.ticker
    a2._str = lambda self=a2:"a2: %d" % self.ticker

    print a1
    print a2    

    a1.ticker = 100
    print a1

main()

the output is :

a1: 1
a2: 2
a1: 100

answered May 8, 2012 at 5:43

HYRY

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