Difficulty parsing a double - String

Question

Thanks for taking the time to answer my question.

I have a double value (let's say 22.35). I need to parse it into a String and get 2235. The following code is not working properly.

double totalPrice = 22.35;
DecimalFormat df = new DecimalFormat("#.##");
String[] temp = df.format(totalPrice).split(".");
String amount = temp[0] + temp[1];

I keep getting an exception ArrayIndexOutOfBounds. What is another way to do this? Thanks in advance!

@AndrewThompson - Looks like an answer to me, with perhaps a sentence or two for explanation. +1 — jamesmortensen
– jamesmortensen, Commented May 21, 2012 at 2:04
@jmort253 Great comment! :) Let's hope that it 'sounds better' (as in - does not get deleted) the way you said it. — Andrew Thompson
– Andrew Thompson, Commented May 21, 2012 at 2:15

user unknown · Accepted Answer · 2012-05-21 02:08:03Z

4

If your values don't exceed, after multiplication by 100, MAX_INT, multiply them:

double totalPrice = 22.35;
int iPrice = (int) (totalPrice * 100);
String sPrice = "" + iPrice;

answered May 21, 2012 at 2:08

user unknown

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3 Comments

user unknown Over a year ago

@AndrewThompson: Sorry, forgot to cast.

jamesmortensen Over a year ago

@userunknown - Congrats on the 10k!

user unknown Over a year ago

@jmort253: Thanks. The last 2000 happen by themselves.

Zach · Accepted Answer · 2012-05-21 02:15:21Z

0

What about:

double totalPrice = 22.35;
DecimalFormat df = new DecimalFormat("#.##");
String price = df.format(totalPrice).replace(".", "");

answered May 21, 2012 at 2:15

Zach

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Comments

Jin · Accepted Answer · 2012-05-21 02:51:59Z

0

Maybe you can do it like this: just change the regex "." to " \."!

String[] temp = df.format(totalPrice).split("\\.");

answered May 21, 2012 at 2:51

Jin

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Comments

A Java Bean · Accepted Answer · 2012-05-21 13:04:56Z

0

This will work no matter how high a number you try to apply it to:

double num = 22.35;
String concatenate = "" + num;
String parsedNum = concatenate.replace(".", "");

Hope this helps you.

answered May 21, 2012 at 13:04

A Java Bean

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