Python regular expression split() string

Question

I'm quite new to regular expressions in Python. I have the following string and want to split them into five categories. I just use the split(), but it will just split according to white spaces.

s = "1 0 A10B 1/00 Description: This is description with spaces"
sp = s.split()
>>> sp
["1", "0", "A10B", "1/00", "Description:", "This", "is", "description", "with", "spaces"]

How can I write a regular expression to make it split like the following?

 ["1", "0", "A10B", "1/00", "Description: This is description with spaces"]

Roman Bodnarchuk · Accepted Answer · 2012-05-22 07:41:32Z

10

You may simply specify a number of splits:

s.split(' ', 4)

answered May 22, 2012 at 7:41

Roman Bodnarchuk

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cytinus · Accepted Answer · 2012-05-22 07:46:01Z

2

The second argument to split() is the maximum number of splits to perform. If you set this to 4, the remaining string will be item 5 in the list.

 sp = s.split(' ', 4)

answered May 22, 2012 at 7:46

cytinus

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tuxuday · Accepted Answer · 2012-05-22 07:45:08Z

1

Not a perfect solution. But for a start.

>>> sp=s.split()[0:4]
>>> sp.append(' '.join(s.split()[4:]))
>>> print sp
['1', '0', 'A10B', '1/00', 'Description: This is description with spaces']

answered May 22, 2012 at 7:45

tuxuday

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