Array to object

Question

I wrote a custom framework. Which uses the .ini type of config file.

Say, if I have a constant assigned in the .ini file as

[production]
db.mongo.hostName = localhost

I am currently parsing this through parse_ini_file() function.

The result will be

$config[production][db.mongo.hostname] = "localhost";

Now I wanna turn this array to an object which should go like

$config->db->mongo->hostname

I tried exploding it with '.', but then I am stuck with forming this as an above iterative object.

Can someone please help me with this.

richardcastera.com/blog/…

D-Rock
– D-Rock

2012-06-25 11:36:05 +00:00
Commented Jun 25, 2012 at 11:36 — D-Rock
– D-Rock, Commented Jun 25, 2012 at 11:36
Exact Duplicate: stackoverflow.com/questions/1869091/…

Riz
– Riz

2012-06-25 11:36:10 +00:00
Commented Jun 25, 2012 at 11:36 — Riz
– Riz, Commented Jun 25, 2012 at 11:36
Zend_Config_Ini already does this quite nicely.

Jon Skarpeteig
– Jon Skarpeteig

2012-06-25 11:36:17 +00:00
Commented Jun 25, 2012 at 11:36 — Jon Skarpeteig
– Jon Skarpeteig, Commented Jun 25, 2012 at 11:36
What is so bad with $config->{db.mongo.hostname}?

hakre
– hakre

2012-06-25 13:33:27 +00:00
Commented Jun 25, 2012 at 13:33 — hakre
– hakre, Commented Jun 25, 2012 at 13:33
possible duplicate of String with array structure to Array

hakre
– hakre

2012-06-25 13:34:35 +00:00
Commented Jun 25, 2012 at 13:34 — hakre
– hakre, Commented Jun 25, 2012 at 13:34

hakre · Accepted Answer · 2012-06-25 14:57:51Z

The following is a rudimentary class that has a single function to import the ini array as you have specified it:

/**
 * Config "Class"
 * @link http://stackoverflow.com/q/11188563/367456
 */
class Config
{
    public function __construct(array $array = array())
    {
        $this->importIniArray($array);
    }

    public function importIniArray(array $array)
    {
        foreach ($array as $key => $value) {
            $rv = &$this;
            foreach (explode('.', $key) as $pk) {
                isset($rv->$pk) || $rv->$pk = new stdClass;
                $rv = &$rv->$pk;
            }
            $rv = $value;
        }
    }
}

I only added the __construct function because you re-use the variable. Usage:

$config = parse_ini_file($path);

$config = new Config($config['production']);

print_r($config);

Exemplary output:

Config Object
(
    [db] => stdClass Object
        (
            [mongo] => stdClass Object
                (
                    [hostname] => localhost
                    [user] => root
                )

        )

)

Edit: You can also solve the problem to locate the array member at time of access. I compiled a little example that behaves similar and it explodes nothing. I called it DynConfig because as you'll see it's dynamic (or magic):

$config = new DynConfig($config['production']);
var_dump($config);
echo $config->db->mongo->hostname; # localhost

The var_dump shows that the array is just preserved internally:

object(DynConfig)#1 (1) {
  ["array":"DynConfig":private]=>
  array(2) {
    ["db.mongo.hostname"]=>
    string(9) "localhost"
    ["db.mongo.user"]=>
    string(4) "root"
  }
}

So how does this work? Each time you access a property, either a key exists or the prefix is extended and the same object is returned. That's in the __get function:

/**
 * Config "Class"
 * @link http://stackoverflow.com/q/11188563/367456
 */
class DynConfig
{
    private $array;

    public function __construct($array)
    {
        $this->array = $array;
    }

    public function __get($name)
    {
        static $prefix = '';
        $k = $prefix .= $name;
        if (isset($this->array[$k])) {
            $prefix = '';
            return $this->array[$k];
        }
        $prefix .= '.';
        return $this;
    }
}

However, this is of experimental nature. The first suggestion is much more direct and much easier to deal with. Keep in mind that your config object should be really simple, it just needs to store some values and that's it.

I am already using php magic functions and singleton pattern in my Config class... Thank you... This is so cool... DynConfigAccess nis so cool..
No, actually I made a mistake, this does not need a second class. I edit the answer. And don't use the singleton antipattern, also magic is not really helpful in the long run. you will introduce problems.

Lake · Accepted Answer · 2012-06-25 12:00:33Z

2

You can done it as below

function assignTo($obj,$keys,$value)
{
        if(count($keys) > 1)   
        {                      
                $h = array_shift($keys);        
                $obj->$h = $obj->$h ? $obj->$h : new stdClass();
                assignTo($obj->$h,$keys,$value);
        }                      
        else                   
        {                      
                $obj->$keys[0] = $value;        
        }
}
$config['production']['db.mongo.hostname'] = "localhost";
$config['production']['db.mongo.password'] = "1234567";
$config['production']['version'] = "1.0";

$object = new stdClass();      
foreach($config['production'] as $key=>$value)
{
        assignTo($object,explode('.',$key),$value);
}                              
print_r($object);

Which would output:

stdClass Object
(
    [db] => stdClass Object
        (
            [mongo] => stdClass Object
                (
                    [hostname] => localhost
                    [password] => 1234567
                )

        )

    [version] => 1.0
)

answered Jun 25, 2012 at 12:00

Lake

9134 silver badges6 bronze badges

3 Comments

hakre Over a year ago

@Lake: In case you want to learn some tricks, take a look at this duplicate question and it's answers: stackoverflow.com/q/8537148/367456

Karthik Over a year ago

@hakre It is the duplicate... But to be honest for all the key words I searched I couldn't end up in that page.

hakre Over a year ago

@Karthik: Sure, it's hard to find stuff sometimes. The most important stuff is to have it cross-linked I'd say, it's not even and exact "exact" duplicate, because that one is about arrays and yours objects (however those two are close in PHP).

Edson Medina · Accepted Answer · 2012-12-07 11:20:09Z

0

// assuming $var is a multidimensional array
$obj = json_decode (json_encode ($var), FALSE);

answered Dec 7, 2012 at 11:20

Edson Medina

10.3k4 gold badges43 silver badges53 bronze badges

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