Button click action in android?

Question

I have two buttons in android. Btn1 and Btn2. I need to show Btn1 by default and when is is clicked I need to show Btn2 in place of Btn1. Again when Btn2 is clicked, it should be replaced with Btn2. Please help me with some example..

My Code:

btn1 = (ImageView) findViewById(R.id.firstbtn);

        btn2 = (ImageView) findViewById(R.id.secondbutton);
        btn2.setVisibility(ImageView.GONE);

        btn1.setOnClickListener(new OnClickListener() {
            @Override
            public void onClick(View v) {

                btn2.setVisibility(ImageView.VISIBLE);
            }
        });

        btn2.setOnClickListener(new OnClickListener() {
            @Override
            public void onClick(View v) {

                btn2.setVisibility(ImageView.GONE);




            }

        });

Thanks in advance

Kevin · Accepted Answer · 2014-01-12 01:50:05Z

6

You can use same button and change its label alternatively and as per level you can put the check and perform appropriate work.

As per your updated code get to know your are using ImageView so try this

   ImageView btn = (ImageView) findViewById(R.id.secondbutton);
    btn.setTag("1");//can use one empty String "" and null instead of "1" and "2" for optimization

        btn.setOnClickListener(new OnClickListener() {
            @Override
            public void onClick(View v) {

                Object obj = v.getTag();

                if(obj instanceof String){
                     if("1".equals(obj)){
                         v.setTag("2");
                         //Your first button state 
                     }else if("2".equals(obj)){
                         v.setTag("1");
                         //Your second button state 
                     }

                }

...

If your case is specific for two buttons then you can use two String compare operations

ImageView btn = (ImageView) findViewById(R.id.secondbutton);
  btn.setTag(null);

    btn.setOnClickListener(new OnClickListener() {
        @Override
        public void onClick(View v) {

            if(v.getTag() instanceof String){
                     v.setTag(null);
                     //Your first button state 
            } else {
                      v.setTag("");
                     //Your second button state 
            }

If you want to make your code work right

btn1 = (ImageView) findViewById(R.id.firstbtn);

        btn2 = (ImageView) findViewById(R.id.secondbutton);
        btn2.setVisibility(ImageView.GONE);

        btn1.setOnClickListener(new OnClickListener() {
            @Override
            public void onClick(View v) {

                v.setVisibility(ImageView.GONE);
                btn2.setVisibility(ImageView.VISIBLE);

            }
        });

        btn2.setOnClickListener(new OnClickListener() {
            @Override
            public void onClick(View v) {

                v.setVisibility(ImageView.GONE);
                btn1.setVisibility(ImageView.VISIBLE);

            }

        });

edited Jan 12, 2014 at 1:50

Kevin

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answered Jun 29, 2012 at 6:47

Dheeresh Singh

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2 Comments

Dheeresh Singh Over a year ago

Please let us know if code required ... I think it's simple you will get button view in onClick(View v)

user1448108 Over a year ago

See my code. By default the first btn is displaying and when i click on it the second btn will display along with first btn and when again the second btn is clicked it will be gone and only first btn is remaining. But everytime i want to display only one btn.help me plz

Khan · Accepted Answer · 2012-06-29 07:02:35Z

change this

btn2.setOnClickListener(new OnClickListener() {
        @Override
        public void onClick(View v) {

            btn2.setVisibility(ImageView.GONE);
        }

    });

by

btn2.setOnClickListener(new OnClickListener() {
        @Override
        public void onClick(View v) {

            btn2.setVisibility(View.GONE);
            btn1.setVisibility(View.VISIBLE);
        }

    });

and this

 btn1.setOnClickListener(new OnClickListener() {
        @Override
        public void onClick(View v) {

            btn2.setVisibility(View.VISIBLE);
        }
    });

by

  btn1.setOnClickListener(new OnClickListener() {
        @Override
        public void onClick(View v) {
            btn1.setVisibility(View.GONE);
            btn2.setVisibility(View.VISIBLE);
        }
    });

Rendy · Accepted Answer · 2012-06-29 06:50:30Z

0

You can create two buttons in layout with same exact positions, then you can set visibility and action of each button that you want

answered Jun 29, 2012 at 6:50

Rendy

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Comments

Guillermo Blasco · Accepted Answer · 2012-06-29 06:50:44Z

0

Can use method visible() to fix its visibility. ToggleButton or one button and toggle the text on click event should work better than two buttons.

answered Jun 29, 2012 at 6:50

Guillermo Blasco

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