Conditional preg_match_all

Question

I have data in format:
Randomtext1 (random2,random4) Randomtext2 (ran dom) Randomtext3 Randomtext4 (random5,random7,random8)

So I would like to recognize the both the Randomtext-part and the text with in brackets, if it is there with preg_match_all, but im not sure how to get it done. The stuff in the brackets goes together with the Randomtext-part and some of the Randomtext-parts have it and some of them dont.

This is what I have so far, and it works in most cases, but if the text doesnt have any brackets, then it matches the whole thing to one.
preg_match_all("/([a-zA-Z]+)\s+(?([a-zA-Z, ]*))?/",$text,$matches);

Any ideas?

Ωmega · Accepted Answer · 2012-06-29 20:07:24Z

1

preg_match_all("/\b\w+\b(?:\s*\(.*?\)|)/", $text, $matches);

edited Jun 29, 2012 at 20:07

answered Jun 29, 2012 at 20:00

Ωmega

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3 Comments

Kemu79 Over a year ago

Thank you! With tiny changes I got the pattern changed to get just the information that I needed!

Ωmega Over a year ago

@Kemu79 - what is the change you have needed to do?

Kemu79 Over a year ago

I changed the pattern to /\b(\w+)\b(?:\s*((.*?))|)/ to save the texts as I needed.

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