PowerShell Regex to find " Version 12.3 "

Question

In a string such as:

CustomerDisplayVersionNumber : Version 12.3 (build 567.89)

How can I, using a regex, return true if the version number is exactly 12.3

There is the slight, but real possibility that the version number might contain a service pack version. For example

CustomerDisplayVersionNumber : Version 12.3.4 (build 567.89)

Which leads me to believe it will be safer to check for [space]Version 12.3.nnnn[space].

Regex [space]Version 12.3.nnnn[space] will not match your first example Version 12.3 — Akim
– Akim, Commented Jul 11, 2012 at 16:40

Akim · Accepted Answer · 2012-07-11 16:36:19Z

2

Regex "\sVersion (\d+\.\d+(\.\d+)?)\s" will satisfy all provided examples

 @('CustomerDisplayVersionNumber : Version 12.3 (build 567.89)', 'CustomerDisplayVersionNumber : Version 12.3.4 (build 567.89)', 'CustomerDisplayVersionNumber : Version 12.3.9999 (build 567.89)') | % { [regex]::Match($_, "\sVersion (\d+\.\d+(\.\d+)?)\s").Success }

answered Jul 11, 2012 at 16:36

Akim

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burning_LEGION · Accepted Answer · 2012-07-11 16:10:00Z

1

use this regex \s+Version \d+\.\d+\.\d+\s+

answered Jul 11, 2012 at 16:10

burning_LEGION

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