Regex in powershell for getting assembly version number

Question

I am trying to create a script that will find and return the assembly version from the solution. It covers some of the test scenarios, but I cannot find the correct regex that will check is the version in correct format (1.0.0.0 is ok, but 1.0.o.0) and that contains 4 digits? Here is my code.

function Get-Version-From-SolutionInfo-File($path="$pwd\SolutionInfo.cs"){
$RegularExpression = [regex] 'AssemblyVersion\(\"(.*)\"\)'
$fileContent = Get-Content -Path $path
foreach($content in $fileContent)
{
    $match = [System.Text.RegularExpressions.Regex]::Match($content, $RegularExpression)
    if($match.Success) {
        $match.groups[1].value
    }
}

}

Try $RegularExpression = [regex] 'AssemblyVersion$"(\d(?:\.\d){3})"$' — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Jul 12, 2021 at 12:40
please add a few lines of your $fileContent collections to see what works with that specific data. — Lee_Dailey
– Lee_Dailey, Commented Jul 12, 2021 at 12:41

mklement0 · Accepted Answer · 2021-07-12 13:47:37Z

1

Change your greedy capture group, (.*), to a non-greedy one, (.*?), so that only the very next " matches.
- The alternative is to use ([^"]*)
To verify if a string contains a valid (2-to-4 component) version number, simply cast it to [version] (System.Version).

Applied to your function, with optimized extraction of the capture group via the -replace operator:

function Get-VersionFromSolutionInfoFile ($path="$pwd\SolutionInfo.cs") {
  try {
    [version] $ver = 
      (Get-Content -Raw $path) -replace '(?s).*\bAssemblyVersion\("(.*?)"\).*', '$1'
  } catch {
    throw
  }
  return $ver
}

edited Jul 12, 2021 at 13:47

answered Jul 12, 2021 at 13:37

mklement0

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