Is there a way in Django to accept 'n' parameters which are delimited by a '/' (forward slash)?
I was thinking this may work, but it does not. Django still recognizes forward slashes as delimiters.
(r'^(?P<path>[-\w]+/)$', 'some.view', {}),
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What do you mean by accept parameters?AlbertoPL– AlbertoPL2009-07-17 19:57:26 +00:00Commented Jul 17, 2009 at 19:57
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1The reason that doesn't work is becuase [-\w]+ includes a hyphen and \w (which is alphanumeric + underscore). You need to expand your criteria to include a /, either by adding / to the character class or by (as per Ian's answer) using something more liberal to begin with, like .*Jason C– Jason C2009-07-17 20:16:06 +00:00Commented Jul 17, 2009 at 20:16
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2 Answers
Add the right url to your urlpatterns:
# ...
("^foo/(.*)$", "foo"), # or whatever
# ...
And process it in your view, like AlbertoPL said:
fields = paramPassedInAccordingToThatUrl.split('/')
Comments
Certainly, Django can accept any URL which can be described by a regular expression - including one which has a prefix followed by a '/' followed by a variable number of segments separated by '/'. The exact regular expression will depend on what you want to accept - but an example in Django is given by /admin URLs which parse the suffix of the URL in the view.
