Sending an object as a parameter in PHP, without instantiating it

Question

How to send an object as paramater in a function call? I don't want to instantiate the object when passing it, so myFunction( new myObject() ) wouldn't work.

I want myFunction to be able to instantiate the object later. I'm just not sure how to pass a class around in this manner.

Community · Accepted Answer · 2017-05-23 10:34:29Z

3

Pass the class name as a string, and instantiate it.

https://stackoverflow.com/a/4578343/362536

function ($className) {
    $object = new $className();
}

edited May 23, 2017 at 10:34

CommunityBot

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answered Jul 17, 2012 at 18:17

Brad

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1 Comment

shane Over a year ago

Ah! I thought as much but I thought there may be another way without using strings. It works though. Good enough for me. Thank you.

Ivan Pintar · Accepted Answer · 2012-07-17 18:20:08Z

2

You could pass a string and do:

myFunction($class) {
    $object = new $class();
}

But a better OOP approach would be to pass a factory object and let the factory create the object:

class MyFactory {
    public function create() { 
        return new myObject; 
    }
}

myFunction(MyFactory $factory) {
    $object = $factory->create();
}

answered Jul 17, 2012 at 18:20

Ivan Pintar

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