how to set a passed function in javascript

Question

I am creating a new object variable and passing an object as an argument:

var obj = new test({
    first : $('#fname').val(),
    last : $('#lname').val(),
    fn : function() {
        alert(this.first + " " + this.last);
    }
});

This is the called function when creating the above variable:

var test = function(obj) {
    this.fn = function() {
        alert("No custom function was made.");
    }

    this.first = obj.first;
    this.last = obj.last;
    if(obj.fn)
        this.fn = obj.fn(); //I also tried it without the '()' after 'obj.fn'
};

The first and last variables are fine, but I cannot figure out how to get the custom function that is passed to be set.

Glen Hughes · Accepted Answer · 2012-07-28 04:39:57Z

2

You mentioned that you tried removing the '()' after 'obj.fn'... seems to work when I do that. Here's the link to verify: http://jsfiddle.net/TD93x/3/

edited Jul 28, 2012 at 4:39

answered Jul 28, 2012 at 4:34

Glen Hughes

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1 Comment

Noah Passalacqua Over a year ago

mhmm wow ok idk why but it worked. i already tried that a bunch of times..... -_- thanks!

Marco Souza · Accepted Answer · 2012-07-28 04:33:42Z

2

it worked for me

var test = function(obj) {
    this.fn = function() {
        alert("No custom function was made.");
    }

    this.first = obj.first;
    this.last = obj.last;
    if(obj.fn)
        this.fn = obj.fn;
};

edited Jul 28, 2012 at 4:33

answered Jul 28, 2012 at 4:21

Marco Souza

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1 Comment

Noah Passalacqua Over a year ago

mhmm wow ok idk why but it worked. i already tried that a bunch of times..... -_- thanks!

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