Casting to unsigned char in C

Question

I am facing a following problem: When trying to do cast to an unsigned char I get unexpected values. The code that I am using:

unsigned char MyVal1  = ((0xF1E3 && 0xff00) >> 8);
unsigned char MyVal2 = (unsigned char)((0xF1E3 && 0xff00) >> 8);
unsigned char MyVal3 = (unsigned char)((0xF1E3 && 0xff));

I am storing all three variables in an array.

The output I am getting (looking at the values in array; array is unsigned char array):

0x00 
0x00
0x01

while I was expecting:

0xF1 
0xF1
0xE3

Could someone be kind to help me out in what am I doing wrong?

yuri kilochek · Accepted Answer · 2012-08-03 10:40:53Z

12

Operators && and & do not work the same on integers. Your operands are first converted to bool (zero/nonzero) and then anded together.

answered Aug 3, 2012 at 10:40

yuri kilochek

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1 Comment

Bo. Over a year ago

Checkmate.... It has been a long day and I totally forgot that I was not using bitwise operator.... Much appreciated.....

ecatmur · Accepted Answer · 2012-08-03 10:41:38Z

10

&& is the boolean and operator; it gives 1 if both its operands are non-zero and 0 otherwise. You want the bitwise and operator, &, which gives 1 or 0 in each bit of its operands.

answered Aug 3, 2012 at 10:41

ecatmur

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