Displaying empty spaces in a string

Question

I am busy with a practical. I have to enter a string or a message and have to convert it to Morse code: 'A' = .- 'B' = -... ecs.

I can do that with no problem by using a series of if statements.

for(int i = 0;i < stringvalue.length();i++)
{
    if(stringvalue == 'A')
        cout << ".-";
        //there is 26 if statements

}

But when i enter a string, eg.

"Testing data"

Only the first part of the string is converted(test is converted) to Morse.

Why does it not convert the part after the space. If there is a space in the string it must output "/ ".

Using cin >> will break at the space. Look at using getline instead: en.cppreference.com/w/cpp/string/basic_string/getline — BoBTFish
– BoBTFish, Commented Aug 6, 2012 at 9:28
Also, instead of using 26 ifs, maybe you could use a table (array) of Morse code values, and look up each letter in the table. — BoBTFish
– BoBTFish, Commented Aug 6, 2012 at 9:35

jxh · Accepted Answer · 2012-08-06 09:29:16Z

3

If your input routine looks like this:

std::string input;
std::cin >> input;

The input is read up to the first whitespace character. To read the whole line, you can use std::getline.

std::getline(std::cin, input);

answered Aug 6, 2012 at 9:29

jxh

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1 Comment

Jonathan Geers Over a year ago

Thank you that helped. I will accept your answer in 10 minutes;

ecatmur · Accepted Answer · 2012-08-06 09:30:47Z

2

Because you're reading the string from stdin using cin >> stringvalue. The C++ operator>>(istream, string) stops after whitespace; it reads only a single space-separated token at a time.

Instead, use getline:

std::getline(std::cin, stringvalue);

answered Aug 6, 2012 at 9:30

ecatmur

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