Problem in accepting a blank space to string in c++

Question

I wrote this code to obtain name. telephone and address of a person and then i input these into class object variables:

#include<iostream>
#include<cstdlib>
#include<fstream>
#include<string>
using namespace std;

class contact{
public:
    string name;//ALL CLASS VARIABLES ARE PUBLIC
    unsigned int phonenumber;
    string address;

    contact(){//Constructor
        name= "Noname";
        phonenumber= 0;
        address= "Noaddress";
    }

    /*void input_contact_name(string s){//function to take contact name
        name=s;
    }
    void input_contact_number(int x){//function to take contact number
        phonenumber=x;
    }
    void input_contact_address(string add){//function to take contact address
        address=add;
    }*/
};

int main(){
    contact *d;
    d= new contact[200];
    string name,add;
    int choice;//Variable for switch statement
    unsigned int phno;
    static int i=0;//i is declared as a static int variable
    bool flag=false;
    cout<<"\tWelcome to the phone Directory\n";//Welcome Message
    cout<<"Select :\n1.Add New Contact\n2.Update Existing Contact\n3.Delete an Existing Entry\n4.Display All Contacts\n5.Search for a contact\n6.Exit PhoneBook\n\n\n";//Display all options
    cin>>choice;//Input Choice from user
    while(!flag){//While Loop Starts
        switch(choice){//Switch Loop Starts
        case 1:
            cout<<"\nEnter The Name\n";
            cin>>name;

            d[i].name=name;
            cout<<"\nEnter the Phone Number\n";
            cin>>phno;
            d[i].phonenumber=phno;
            cout<<"\nEnter the address\n";
            cin>>add;
            d[i].address=add;
            i++;

            flag=true;
        }
    }
    return 0;
}

However If I enter the name separated with its surname, the code bypasses the next cins and exits. Can some one help me out why this happens? Same happens when I enter 10 digit cell no. Thanks in advance

Please put some effort into formatting your code. It would also be a good idea to post shorter samples. — Mat
– Mat, Commented Apr 15, 2011 at 10:09
I suggest you accept the answer given by ildjarn. It's been some time and it is the correct answer. — Mephane
– Mephane, Commented Jun 8, 2011 at 7:42

ildjarn · Accepted Answer · 2011-04-15 11:08:09Z

6

Use std::getline() instead of operator>> to extract a std::string containing whitespace.

edited Apr 15, 2011 at 11:08

answered Apr 15, 2011 at 10:17

ildjarn

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2 Comments

Tony The Lion Over a year ago

I wondered what the problem is with operator>> and strings with spaces?

Mephane Over a year ago

operator>> reads one element. Typically, an element is considered to be terminated by the next whitespace, as is the case for std::string and all primitives. std::getline is your friend, as the answer says.

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