Rendering Django template to URL with querystring

Question

I have profile edit page with several tabs. Each tab is a separate page, so when I access it, I add "tab" parameter:

/edit/?tab=general 
/edit/?tab=contacts

When user finishes to fill a form on one of these tabs (for example, /edit/?tab=general), he submit it. If form is not valid, I need to render it with errors. Browser URL input need to be filled with /edit/?tab=general, but when I render page, URL is /edit/.

Can I change it somehow? Thanks.

Code:

def _profile_edit_general(request):
profile = request.user.get_profile()
if request.method == 'POST':
    form = forms.ProfileEditGeneralForm(request.POST, instance=profile)
    if form.is_valid():
        form.save()
else:
    form = forms.ProfileEditGeneralForm(instance=profile)
return render_template(request, 'profiles/edit/general.html', {
    'profile_edit_general_form': form
})

@login_required
def profile_edit(request):
if request.method == 'POST':
    if 'profile_edit_general_submit' in request.POST:
        return _profile_edit_general(request)
else:
    tab = request.GET.get('tab')
    if tab == 'general':
        return _profile_edit_general(request)
    else:
        return Http404

Andrew Ingram · Accepted Answer · 2012-08-06 12:30:00Z

3

It sounds like the problem is that your form action doesn't include the query string.

Normally with Django forms and views, you'll be posting to the same URL as you're already on, which means you can do something like this:

<form method="post" action="?tab={{ current_tab }}">

...

</form>

Where current_tab is a context variable indicating which tab is selected. Based on your code at the moment, you'll need to add it to the dict in your render_template call. If you're using JavaScript to switch tabs, you'll need to update the action attribute when the tab switches too.

answered Aug 6, 2012 at 12:30

Andrew Ingram

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