how to use javascript's regex to match the second number?

Question

this is my string.

var id = "timesheet_entries_attributes_0_entry_overtimes_attributes_0_code_id"

question is I want to replace the last zero with another number.

the zero's position is always change. But there are only two zeros in the string. And they can't be together.

such as :

var num = "2"; ("timesheet_entries_attributes_0_entry_overtimes_attributes_0_code_id").replace(/\d/,num);

but it always replace the first zero.

SoS!

HBP · Accepted Answer · 2012-08-10 04:54:27Z

1

id.replace (/(\d+)(?=\D+$)/, '2')

This version replaces the LAST number in the string.

answered Aug 10, 2012 at 4:54

HBP

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xdazz · Accepted Answer · 2012-08-10 04:08:51Z

0

var id = "timesheet_entries_attributes_0_entry_overtimes_attributes_0_code_id";
var num_replace = 5;
id = id.replace(/(\d+.*)\d+/, "$1"+num_replace);

answered Aug 10, 2012 at 4:08

xdazz

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Ricardo Lohmann · Accepted Answer · 2012-08-10 04:28:03Z

0

Just a different way to solve:

var id = "timesheet_entries_attributes_0_entry_overtimes_attributes_0_code_id",
    matchIndex = 1,
    replace = 300,
    count = -1;

id = id.replace(/\d+/g, function(number) {
    count++;
    return (count == matchIndex) ? replace : number;
});

demo

edited Aug 10, 2012 at 4:28

answered Aug 10, 2012 at 4:08

Ricardo Lohmann

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1 Comment

zerkms Over a year ago

And how to replace the second number?

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