i have php page with get 2 parameters $link and $text i want get $link parameter with all parameters inside it example
test.php?link=www.google.com?test=test&test2=test2&text=testtext
i want get link = 'www.google.com?test=test&test2=test2' and get text = testtext
i use this php script
<?php
$text = $_GET['text'];
$link = $_GET['link'];
echo $text;
echo $link;
?>
output
testtext
www.google.com?test=test
You should encode your parameters before using it on GET.
echo '<a href="test.php?link=' . urlencode('www.google.com?test=test&test2=test2') . '&text=' . urlencode('testtext') . '">test</a>';
In that way, there is no conflicts between google vars and yours.
See urlencode() manual for details.
$link_mod = str_replace("?", "&", $_GET['link']);
$array = explode("&", $link_mod);
unset($array[0]); #get rid of www.google.com segment
$segments = array();
foreach ($array as $line) {
$line_array = explode('=', $line);
$key = $line_array[0];
$value = $line_array[1];
$segments[$key] = $value;
}
print_r($segments);
If you want to pass a URL as a parameter, you must escape it. Otherwise the parameters will appear as $_GET parameters inside your script.
You have to generate your link using urlencode():
$link = "test.php?link=".urlencode("www.google.com?test=test&test2=test2")."&text=" . urlencode("testtext");
Also use quotation marks when using strings:
$text = $_GET['text'];
$link = $_GET['link'];
