Exclude IDs from PHP foreach loop

Question

I am trying to exclude more than one ID from a select list that is populated by a foreach loop:

$types = new Type();
$types->where('id !=', 13)->order_by('name')->get();
$data['types'] = $types;

<select class="styled" name="form[type_id]">
<option value="0"> - select one - </option>
<?php foreach ($types as $t): ?>
<option value="<?=$t->id?>" <?=check_selected($t->id, $i->type_id)?>><?=$t->name?></option>
<?php endforeach; ?>
<option value="13" <?=check_selected(13, $i->type_id) ?>>Other</option>
</select>

So at the moment it will exclude ID 13 (and add it manually to the bottom), but how do I add more IDs to be excluded?

Thanks in advance.

mgraph · Accepted Answer · 2012-09-09 22:29:39Z

2

try this:

...
$exclude = array(13,25);// add IDs to exlude
....
<?php foreach ($types as $t): ?>
   <?php if(!in_array($t->id, $exclude)){ ?>// if the ID is in the exlude array don't add it
      <option value="<?=$t->id?>" <?=check_selected($t->id, $i->type_id)?>><?=$t->name?></option>
   <?php } ?>
<?php endforeach; ?>
...

edited Sep 9, 2012 at 22:29

answered Sep 9, 2012 at 22:22

mgraph

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