php class error handling

Question

class Foo {
    private $_bar;

    public function getBar() {
        return $this->_bar;
    }
}
$b = new Foo(); 
$b->xxx(); //xxx is an udefined method.

How to enhance the following class to throw a notice if undefined methods is called?

you can do it like the answer says, but why would you need to do something like that? — Jarry
– Jarry, Commented Sep 14, 2012 at 19:05
just education :) Thus, i don't know if its good practice ... — Guntis
– Guntis, Commented Sep 14, 2012 at 19:20
in that case, i think that in the 'standard' object paradigm it isnt. you just need to design your classes in a way that an object will never be asked for a method that doesnt have. but if you want to learn look for books about object oriented proggraming — Jarry
– Jarry, Commented Sep 14, 2012 at 19:26

JvdBerg · Accepted Answer · 2012-09-14 19:04:28Z

3

class Foo {
    private $_bar;

    public function getBar() {
        return $this->_bar;
    }

    public function __call($name, $params)
    {
       throw new Exception("Method $name does not exists!");
    }
}

answered Sep 14, 2012 at 19:04

JvdBerg

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dead · Accepted Answer · 2012-09-14 19:03:09Z

3

You have to define a the __call( $methodName , $args ) method.

And throw your own exception from there.

answered Sep 14, 2012 at 19:03

dead

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Comments

Madara's Ghost · Accepted Answer · 2012-09-14 19:01:57Z

0

A PHP warning would be thrown like any other time when you call an undefined function. You need to enable it with error_reporting(E_ALL);.

answered Sep 14, 2012 at 19:01

Madara's Ghost

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1 Comment

just somebody Over a year ago

calls to nonexistent methods are actually fatal errors, no matter what the error_reporting level is.

xkeshav · Accepted Answer · 2012-09-14 19:04:12Z

0

write __call in Class Foo

function __call( $functionName, $argumentsArray ) {
      echo "Function $functionName does not exist";
    }

Reference

answered Sep 14, 2012 at 19:04

xkeshav

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