Extract a range of array in Powershell

Question

Assume there is an array in variable $a that is created like this,

$a  = ,@(1,2,3)
$a += ,@(4,5,6)
$a += ,@(7,8,9)
$a += ,@(10,11,12)

I want to extract part of the array, say $a[1] and $a[2], into another variable, say, $b such that,

$b[0] = @(4,5,6)
$b[1] = @(7,8,9)

I can use a simple for loop to do the task, but I am thinking if there is a more 'elegant' way to do this... may be a one-liner?

Thanks in advance.

Shay Levy · Accepted Answer · 2012-09-18 14:19:27Z

34

You can use the Range operator to slice the array:

$b = $a[1..2]

answered Sep 18, 2012 at 14:19

Shay Levy

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1 Comment

Thank you very much. You made it so easy. :)

Emil · Accepted Answer · 2016-08-12 09:51:08Z

4

It is worth noting the Range operator supports dynamic values - very useful when you want to work out your range dynamically, for example:

$a = @(0,1,2,3,7)
$b = @(4,5,6)
$twotoseven = $a[($a.Length-($a.Length-2))..($a.Length-2)] + $b + $a[-1]

Output:

2 3 4 5 6 7

answered Aug 11, 2016 at 15:53

Emil

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