jQuery plugin call function from function

Question

How can I call a function of jQuery plugin from inside of the same object. I use exact suggested solution http://docs.jquery.com/Plugins/Authoring#Plugin_Methods. From external code I can call this way:

$('div').tooltip("myMethod", an_attr);

But how can I call the same from inside especially form event when 'this' is not the object of plugin.

var methods = {
    var $this = $(this);
    init : function( options ) {
        $this.click(function(){
            $this.fn2("myMethod", an_attr); //is it right way?

        });
    },
    fn2 : function() {
        //but how can I call the myMethod. here ?
    },
    myMethod : function() {...

You don't need to wrap this in $(), it's already a jQuery object. — gen_Eric
– gen_Eric, Commented Oct 16, 2012 at 15:54
Could you elaborate what this should be and what you want to call, in what order? — pimvdb
– pimvdb, Commented Oct 16, 2012 at 16:03

Ed . · Accepted Answer · 2012-10-16 16:21:35Z

1

In fn2 to invoke myMethod you could do the following:

...
fn2: function() {
  methods.myMethod();
}
...

To be sure that myMethod has the same context as all of the others, you could do:

...
fn2: function() {
  methods.myMethod.call(this);
}
...

More details on call() here.

A JS Fiddle here.

answered Oct 16, 2012 at 16:21

Ed .

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2 Comments

Tomas Randus Over a year ago

thank you, it works fine. Is there any way to reach DOM node without sending this by the 'call'.

Ed . Over a year ago

I suppose one answer might be to change each of your functions in methods to always require the jQuery object are the first parameter, and change the line methods[method].apply(this, ...) to ensure the first argument is also this (the jQuery object), then you have the collection of DOM nodes available to you using jQuery.each. An alternative is to use $.proxy...

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