What does the following line of Ruby Do? "integer >> integer"

Question

I am trying to convert some Ruby code into C# but I do not understand what the following line does. Specifically the "challenge >> 24" and similar parts.

challenge = sprintf("%c%c%c%c".encode("ASCII-8BIT"), x(challenge >> 24), x(challenge >> 16), x(challenge >> 8), x(challenge >> 0))

challenge is an integer that is defined earlier in the code. x is a method that takes an integer argument and returns an integer.

I am not expecting anyone to convert it to c# for me, just an explanation would be fine. Thanks.

It's a bit-shift to the right.

lc.
– lc.

2012-10-25 10:20:50 +00:00
Commented Oct 25, 2012 at 10:20 — lc.
– lc., Commented Oct 25, 2012 at 10:20

Community · Accepted Answer · 2017-05-23 10:25:10Z

3

>> is Binary Right Shift Operator.

The left operands value is moved right by the number of bits specified by the right operand.

This may be helpful: Rotate Bits Right operation in Ruby

edited May 23, 2017 at 10:25

CommunityBot

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answered Oct 25, 2012 at 10:22

Azodious

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2 Comments

Mike T Over a year ago

In other words, it divides by 2^24

Joey Over a year ago

If they struggle understanding a shift I doubt they need a rotation.

Pyritie · Accepted Answer · 2012-10-25 10:22:27Z

2

Bit shift to the right, with the number to the right of the >> indicating how many times to shift.

C# has the >> operator too so translating that should be straightforward.

answered Oct 25, 2012 at 10:22

Pyritie

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