Simple ascii replacement - Javascript

Question

I'm looking for a javascript function which takes a string parameter and checks for ascii characters lower than 32, replacing them with empty string -> "". I'm new to javascript so I was wondering whether anyone can point me towards the right direction ?

Thanks in advance for your time.

What I meant was, I want to find and remove any characters within the string that has a lower ascii value than 32 — Pumpkin
– Pumpkin, Commented Nov 15, 2012 at 13:28

Sean Airey · Accepted Answer · 2012-11-15 14:53:01Z

7

Try this:

var replaced = string.replaceAll("[^ -~]", "");

Using ^ negates the characters class, and since space is character 32 in the ASCII table and ~ is the last printable character, you're basically saying "everything that isn't a printable character".

To simply remove all characters from 0-31 use:

var replace = string.replaceAll("\x00-\x1F", "");

edited Nov 15, 2012 at 14:53

answered Nov 15, 2012 at 13:34

Sean Airey

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3 Comments

Sean Airey Over a year ago

See my edit, I've included how to match specific character codes, with 1F being 31.

Vitaly Zdanevich Over a year ago

This will remove french letter à.

Sean Airey Over a year ago

@Vitaly Not at desk ATM, which code is à? You could just add "^à" or "^{insert character code here}" to the regular expression to get it to exclude those from the replacement :)

Joseph Adams · Accepted Answer · 2012-11-15 13:29:10Z

1

If I understand your question correctly you are looking for a regex to use with .replace...

For replacing any printable ascii chars you can use this regex:

/[ -~]/

You will probably have to adjust the range. I recommend changing the tilder since it is the last printable char.

Sorry, I see what you mean! I think you cannot match unprintable chars unless use use their special symbol: i.e. \b \s \n etc.

answered Nov 15, 2012 at 13:29

Joseph Adams

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Comments

lostsource · Accepted Answer · 2012-11-15 13:49:57Z

1

function keepCharsAbove(inStr, charCode) {
  var goodChars = [];
  for(var x = 0; x < inStr.length; x++) {
      if(inStr.charCodeAt(x) > charCode) {
          goodChars.push(inStr.charAt(x));
      }
  }

  return goodChars.join("");
}

Usage:

keepCharsAbove("foo \t bar",32); // returns 'foobar'

edited Nov 15, 2012 at 13:49

answered Nov 15, 2012 at 13:34

lostsource

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1 Comment

Richard Over a year ago

This would probably be better by converting the input to an array of single character strings, filtering the array (Array.filter) and then joining back into a string. (A more functional approach.)

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