Error in output of a simple SAX parser

Question

I saw an example in mykong - http://www.mkyong.com/java/how-to-read-xml-file-in-java-sax-parser/ I tried to make it work for the xml file (below) by making the following modifications to the code in the above page -

1 - Have only two if blocks in startElement() and characters() methods.
2 - Change the print statements in above methods, ie 
    FIRSTNAME and First Name = passenger id
    LASTNAME and Last Name = name

The problem is - In the output, I see the word passenger instead of the value of passenger id. How do i fix that ?

<?xml version="1.0" encoding="utf-8"?>
<root xmlns:android="www.google.com">

<passenger id="001">
<name>Tom Cruise</name>
</passenger>

<passenger id="002">
<name>Tom Hanks</name>
</passenger>

</root>

Java Code

import javax.xml.parsers.SAXParser;
import javax.xml.parsers.SAXParserFactory;
import org.xml.sax.Attributes;
import org.xml.sax.SAXException;
import org.xml.sax.helpers.DefaultHandler;

public class ReadXMLFileSAX{

public static void main(String argv[]) {

try {

SAXParserFactory factory = SAXParserFactory.newInstance();
SAXParser saxParser = factory.newSAXParser();

DefaultHandler handler = new DefaultHandler() {

boolean bfname = false;
boolean blname = false;

public void startElement(String uri, String localName,String qName, 
            Attributes attributes) throws SAXException {

    System.out.println("Start Element :" + qName);

    if (qName.equalsIgnoreCase("passenger id")) {
        bfname = true;
    }

    if (qName.equalsIgnoreCase("name")) {
        blname = true;
    }

}

public void endElement(String uri, String localName,
    String qName) throws SAXException {

    System.out.println("End Element :" + qName);

}

public void characters(char ch[], int start, int length) throws SAXException {

    if (bfname) {
        System.out.println("passenger id : " + new String(ch, start,   length));
        bfname = false;
    }

    if (blname) {
        System.out.println("name : " + new String(ch, start, length));
        blname = false;
    }

}

 };

   saxParser.parse("c:\\flight.xml", handler);

 } catch (Exception e) {
   e.printStackTrace();
   }

   }

}

@BrianAgnew - added the code now. Please let me know if it anything else is required. Thanks — Apple Grinder
– Apple Grinder, Commented Dec 10, 2012 at 9:39
The answer is here - stackoverflow.com/questions/13818129/… — Apple Grinder
– Apple Grinder, Commented Dec 14, 2012 at 8:00

R Kaja Mohideen · Accepted Answer · 2012-12-10 12:28:19Z

1

In the startElement, when it's for "passenger", Attributes argument you get will have that value.

public void startElement(String uri, String localName,
    String qName, Attributes attributes)
        throws SAXException {
    if (qName.equalsIgnoreCase("passenger") && attributes != null){
        System.out.println(attributes.getValue("id"));
    }
}

edited Dec 10, 2012 at 12:28

answered Dec 10, 2012 at 9:43

R Kaja Mohideen

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4 Comments

Apple Grinder Over a year ago

Actually I don't understand the main code properly. I modified my code (below), but i still can't see passenger id. >>>>>>>>>>>>>>>>>>>>>>>>>>public void startElement(String uri, String localName,String qName, Attributes attributes) throws SAXException { System.out.println("Start Element :" + qName); if (localName.equalsIgnoreCase("passenger id")) { System.out.println("Passenger: " + attributes.getValue("id")); } if (qName.equalsIgnoreCase("passenger id")) { bfname = true; } if (qName.equalsIgnoreCase("name")) { blname = true; } }

R Kaja Mohideen Over a year ago

I have updated the code to use qName in startElement. It compares and prints the passenger id.

Apple Grinder Over a year ago

I changed localName to qName, but i get the same problem - there is no id, only passenger word is printed.

R Kaja Mohideen Over a year ago

What implementation of SAXParserFactory and SAXParser you're using? It works clean with my default implementation coming with Java 7.

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