Creating dynamic objects with | separator python

Question

What I want is to solve is something like this

names = ['Aleister', 'Matovu']
args = (Q(name__contains=name[0])|Q(name__contains=name[1]))
queryset.complex_filter(args)

What the problem is I have a names as a dynamic object and its length is not fixed. What I am thinking would work is if I looped though the names and created a dynamic args object but I am not sure what kind of object that is. I am not sure how exactly to do that, so I am stuck.

If you can help around that, that will be really cool or if you can give me an alternative way to go about the same scenario that would be awesome. Thank you

possible duplicate of Django : How to Query model where name contains any word in python list? — glglgl
– glglgl, Commented Dec 12, 2012 at 10:55

Timmy O'Mahony · Accepted Answer · 2012-12-12 11:17:37Z

2

import operator
names = [...]
query = reduce(operator.or_, [Q(name__icontains=name) for name in names])
results = queryset.complex_filter(query)

answered Dec 12, 2012 at 11:17

Timmy O'Mahony

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Community · Accepted Answer · 2017-05-23 11:55:58Z

0

I do not know what Q is in this case, but maybe

import operator
qq = [Q(name__contains=i) for i in name)]
args = reduce(operator.or_, qq)

might help. But as this is the same as Timmy wrote, don't upvote me, but him.

If not, see at this question here.

edited May 23, 2017 at 11:55

CommunityBot

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answered Dec 12, 2012 at 10:53

glglgl

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2 Comments

Aleister Over a year ago

~name__contains==i for i in name~ name__contains is not defined, please add some bit context, thank you

glglgl Over a year ago

Forget it. As I don't know this stuff, I thought it might be a comparison, but is a keyword argument. As said, resort to this other question, or look at Timmy's answer. Updated this answer, but I probably will delete it soon...

Aleister · Accepted Answer · 2012-12-12 12:08:58Z

0

Here is a pretty satisfying solution. If it is ever of any help to anyone

http://bradmontgomery.blogspot.com/2009/06/adding-q-objects-in-django.html

q = Q(content__icontains=term_list[0]) | Q(title__icontains=term_list[0])
for term in term_list[1:]:
    q.add((Q(content__icontains=term) | Q(title__icontains=term)), q.connector)

stories = stories.filter(q)

answered Dec 12, 2012 at 12:08

Aleister

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