I have a loop of checkboxes from a MySql table "exercise" in a form as shown below:
<form id="form1" name="form1" method="POST" action="insertDrills.php">
<table width="100%" border="1" cellspacing="0" cellpadding="0">
<?php do { ?>
<tr>
<td>
<input type="checkbox" name="drillSelect[]" value="<?php echo $row_Recordset1['drillID']; ?>" id="drillSelect" />
<?php echo $row_Recordset1['rubrik']; ?>
</td>
</tr>
<?php } while ($row_Recordset1 = mysql_fetch_assoc($Recordset1)); ?>
<tr>
<td colspan="2">
<input name="spelarID" type="hidden" id="spelarID" value="<?php echo $row_rsSpelare['id']; ?>" />
<input name="date" type="hidden" id="date" value="<? print date("Y-m-d h:i:s"); ?>" />
<input type="submit" name="submit" id="submit" value="Välj övningar" />
<input type="button" value="Avbryt" onclick="window.close();"></button>
</td>
</tr>
</table>
</form>
The value from the hidden fied "spelarID" along with the value from the checkbox array are inserted to a look-up table "exercise_spelare_ref" with this:
<?php
$id = $_POST['spelarID'];
$drills = $_POST['drillSelect'];
$date = $_POST['date'];
$inserts = array();
foreach ($drills as $drills)
$inserts[] = "('$id','$drills','','$date')";
$query = "REPLACE INTO exercise_spelare_ref VALUES ". implode(", ", $inserts);
//echo "query = $query"; // for debugging purposes, remove this once it is working
mysql_query($query) or die(mysql_error());
?>
How can I make values that are in the look-up table marked as "checked" in the form?
There are a solution here https://stackoverflow.com/a/4069477 written by Martin Bean but I cant get it to work?
I have been stuck here for ever, hope anyone can help me out here!
I tried Martin Beans script like:
$uid = $row_rsSpelare['id']; // your logged in user's ID
$exercise = array();
// get an array of exercise
$sql = "SELECT drillID FROM exercise";
$res = mysql_query($sql);
while ($row = mysql_fetch_object($res)) {
$exercise[$row->id] = $row->drillID;
}
// get an array of exercise user has checked
$sql = "SELECT DISTINCT drillID FROM exercise_spelare_ref WHERE id = '$uid'";
$res = mysql_query($sql);
while ($row = mysql_fetch_object($res)) {
$checked[] = $row->drillID;
}
// this would be templated in a real world situation
foreach ($exercise as $id => $drillID) {
$checked = "";
// check box if user has selected this exercise
if (in_array($checked, $id)) {
$checked = 'checked="checked" ';
}
echo '<input type="checkbox" name="drillSelect[]" value="'.$id.'" '.$checked.'/>';
}
But getting a warning:
Warning: in_array() expects parameter 2 to be array, string given in /customers/b/d/e/teeview.se/httpd.www/analys_kund/selectDrills.php on line 158
Line 158 is:
if (in_array($checked, $id)) {
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