python3 - data type of input()

Question

I need to assign a user-provided integer value to an object. My format is as follows:

object = input("Please enter an integer")

The following print tests...

print(type(object))
print(object)

...return <class 'str'> and '1'. Is there a way to set the data type of 'object' to the data type of the user's input value? IOW, such that if object=1, type(object)=int? I know I can set the data type of an input to int using the following:

object = int(input("Please enter an integer"))

In this case, if the user does not provide an int, the console throws a traceback error and the program crashes. I would prefer to test whether the object is in fact an int; if not, use my program to print an error statement and recursively throw the previous prompt.

Please don't use object as a variable name; it's a builtin name used to refer to the Python universal base class. (Plus, it's a terribly generic name to start with.) — nneonneo
– nneonneo, Commented Jan 28, 2013 at 22:36
It has a unique name in my actual code, but I wanted to simplify my question. Still, thanks for your feedback/insight! — Matthew Yanez
– Matthew Yanez, Commented Jan 28, 2013 at 22:50

James Scholes · Accepted Answer · 2013-01-28 22:46:29Z

2

while True:
 try:
  object = int(input("Please enter an integer"))
  break
 except ValueError:
  print("Invalid input.  Please try again")
print(type(object))
print(object)

edited Jan 28, 2013 at 22:46

answered Jan 28, 2013 at 22:40

James Scholes

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Comments

nneonneo · Accepted Answer · 2013-01-28 22:37:31Z

0

You can always catch a "traceback error" and substitute your own error handling.

user_input = input("Please enter an integer")
try:
    user_number = int(user_input)
except ValueError:
    print("You didn't enter an integer!")

answered Jan 28, 2013 at 22:37

nneonneo

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1 Comment

Matthew Yanez Over a year ago

Thanks for prodding me to read more carefully, t'is indeed a ValueError. No such thing as a traceback error! Whoops.

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