Splitting unix output

Question

I'm trying to extract an address from a file.

grep keyword /path/to/file

is how I'm finding the line of code I want. The output is something like

var=http://address

Is there a way I can get only the part directly after the = i.e. http://address , considering the keyword I'm greping for is both in the var and http://address parts

Celada · Accepted Answer · 2013-02-01 17:48:00Z

12

grep keyword /path/to/file | cut -d= -f2-

answered Feb 1, 2013 at 17:48

Celada

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chrisaycock · Accepted Answer · 2013-02-19 05:11:25Z

8

Just pipe to cut:

grep keyword /path/to/file | cut -d '=' -f 2

edited Feb 19, 2013 at 5:11

answered Feb 1, 2013 at 17:48

chrisaycock

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1 Comment

Neil Gaetano Lindberg Over a year ago

I needed a list of theme names from a directory with files like this: theme-xcode.js, where I just needed the "xcode" bit. This answer helped me. I like to understand, so commenting what I learned: -f is the 1-based position of the result of the cut. So, here I get the xcode.js from the first cut, and then just xcode from the second: ls | grep theme | cut -d '-' -f 2 | cut -d '.' -f 1

P.P · Accepted Answer · 2013-02-01 18:01:02Z

5

You can avoid the needless pipes:

awk -F= '/keyword/{print $2}' /path/to/file

edited Feb 1, 2013 at 18:01

answered Feb 1, 2013 at 17:50

P.P

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