I have a string with State name and code like this
KT16(Ottershaw)
Now i need to extract text from (). I need to extract Ottershaw. How can i do this with php.
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2Duplicate of stackoverflow.com/questions/196520/… ?PGallagher– PGallagher2013-02-07 10:16:27 +00:00Commented Feb 7, 2013 at 10:16
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2stackoverflow.com/questions/196520/…Pedro del Sol– Pedro del Sol2013-02-07 10:17:18 +00:00Commented Feb 7, 2013 at 10:17
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4 Answers
should be :
preg_match('/\(([^\)]*)\)/', 'KT16(Ottershaw)', $matches);
echo $matches[1];
1 Comment
Muhammad Raheel
Thanks for quick answer. Regex is great i like the way
Just get the substring between the first opening bracket and the last closing bracket:
$string = "KT16(Ottershaw)";
$strResult = substr($string, stripos($string, "(") +1,strrpos($string, ")") - stripos($string, "(")-1);
4 Comments
m4t1t0
Yeah, not all the problems need a regex
devOp
No. It is also working with
$string = "KT16(Otte (rshaw))";
HamZa
What about
$string = "KT16(Otte) test (rshaw)"; ? I'll still give you +1 thought :pdevOp
Now i understand what you mean... Yes you are right, but it wasn't in the question. I thought it would be nice to get it even there are further brackets in the string.
This is a sample code to extract all the text between '[' and ']' and store it 2 separate arrays(ie text inside parentheses in one array and text outside parentheses in another array)
function extract_text($string)
{
$text_outside=array();
$text_inside=array();
$t="";
for($i=0;$i<strlen($string);$i++)
{
if($string[$i]=='[')
{
$text_outside[]=$t;
$t="";
$t1="";
$i++;
while($string[$i]!=']')
{
$t1.=$string[$i];
$i++;
}
$text_inside[] = $t1;
}
else {
if($string[$i]!=']')
$t.=$string[$i];
else {
continue;
}
}
}
if($t!="")
$text_outside[]=$t;
var_dump($text_outside);
echo "\n\n";
var_dump($text_inside);
}
Output: extract_text("hello how are you?"); will produce:
array(1) {
[0]=>
string(18) "hello how are you?"
}
array(0) {
}
extract_text("hello [http://www.google.com/test.mp3] how are you?"); will produce
array(2) {
[0]=>
string(6) "hello "
[1]=>
string(13) " how are you?"
}
array(1) {
[0]=>
string(30) "http://www.google.com/test.mp3"
}
Comments
The following RegEx should work:
/\[(.*?)\]/
Comments
