I am using a regular expression from although this only extracts the text inside of the brackets, I want to completely remove it:
if( preg_match( '!\(([^\)]+)\)!', $text, $match ) )
$text = $match[1];
E.g I have: my long text string (with another string)
How can I get:
$var1 = "my long text string";
$var2 = "with another string";
// This is all you need
<?php $data = explode('(' , rtrim($str, ')')); ?>
Example:
<?php
$str = 'your long text string (with another string)';
$data = explode('(' , rtrim($str, ')'));
print_r($data);
// output
// Array
// (
// [0] => my long text string
// [1] => with another string
// )
// profit $$$$
?>
$data = preg_split("/[()]+/", $text, -1, PREG_SPLIT_NO_EMPTY);
( and )'s, though.
You could use the code below. But keep in mind that you do need some extra checking to see if there really is an $out[0][0] and $out[0][1]
<?php
$string = "my long text string (with another string)";
preg_match_all("/(.*)\((.*)\)/", $string, $out, PREG_SET_ORDER);
print_r($out);
/*
Array
(
[0] => Array
(
[0] => my long text string (with another string)
[1] => my long text string
[2] => with another string
)
)
*/
$var1 = $out[0][1];
$var2 = $out[0][2];
//$var1 = "my long text string";
//$var2 = "with another string";
?>
I am not so good in regular expression, but you can try this.....
$exp=explode("(", $text);
$text1=$exp[0];
$text2=str_replace(array("(",")"), array('',''), $exp[1]);
trim instead of str_replace'([^\)]+)\(([^\)]+)\)'
Just remove the !-chars and add a another variable field (the name for brackets-area?) and its ready :)
http://www.solmetra.com/scripts/regex/index.php is worth knowing to get some testing quickly done!
this is a very detailed code... you can do it shorter...
<?php
$longtext = "my long text string (with another string)";
$firstParantheses = strpos($longtext,"(");
$firstText = substr($longtext,0,$firstParantheses);
$secondText = substr($longtext,$firstParantheses);
$secondTextWithoutParantheses = str_replace("(","",$secondText);
$secondTextWithoutParantheses = str_replace(")","",$secondTextWithoutParantheses);
$finalFirstPart = $firstText;
$finalSecondPart = $secondTextWithoutParantheses;
echo $finalFirstPart." ------- ".$finalSecondPart;
?>
Why don't you use this workaround:
$vars = explode('@@', str_replace(array('(', ')'), '@@', $text));
It will replace the brackets with @@ and then explode the text to an array. Additionally you can use array_filter to remove possible empty positions.
