Python Syntax Error or Bug?

Question

I've just begun learning Python and I'm using the IDLE ide to learn programming. I've been trying a basic code I saw on the official site but it keeps saying 'Incorrect Syntax' and highlights the keyword 'else' here's the program:

a=40
if a <= 40:
    print("True")
    else:

The 'else' is highlighted and I'm told it's a syntax error. Can anyone tell me what I'm doing wrong?

In Python, Whitespace is part of the syntax. The syntax error lies in your usage of whitespace. — Niklas B.
– Niklas B., Commented Feb 25, 2013 at 11:16
Pro tip: When learning a new language or library, or anything, if you get a syntax error you can assume you did something wrong. 99.99% of the time it is not a bug. — Martijn Pieters
– Martijn Pieters, Commented Feb 25, 2013 at 11:21
@Volatility: Which only illustrates all the more why the OP doesn't understand what is wrong. I indented it to match the original error image. — Martijn Pieters
– Martijn Pieters, Commented Feb 25, 2013 at 11:22

Volatility · Accepted Answer · 2013-02-25 11:16:47Z

3

The else block needs to be indented at the same level as the if block.

if a <= 40:
    print('True')
else:
    print('False')

answered Feb 25, 2013 at 11:16

Volatility

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tttthomasssss · Accepted Answer · 2013-02-25 11:22:47Z

0

You need to fix your identation for the else: clause (even when working on the console). The alignment of else: has to agree with that of the if

answered Feb 25, 2013 at 11:22

tttthomasssss

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