Passing arguments containing white space through a wrapper shell script to python script

Question

I have a wrapper script command.sh as main launch script for my python application, primarily to set some environment variables like PYTHONPATH:

#!/bin/bash

export PYTHONPATH=lib64/python/side-packages
./command.py $*

command.py looks like this:

#!/usr/bin/python

import sys
print sys.argv

Calling the wrapper script like

$ ./command.sh a "b c"

results in ['./command.py', 'a', 'b', 'c'], where I need ['./command.py', 'a', 'b c']

How can I pass parameters which contain spaces to the python script?

Andreas Fester · Accepted Answer · 2013-03-27 14:38:25Z

4

Use $@ instead of $*, and quote it with ":

#!/bin/bash

export PYTHONPATH=lib64/python/side-packages
./command.py "$@"

See bash(1), section "Special Parameters", for more information.

answered Mar 27, 2013 at 14:38

Andreas Fester

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1 Comment

Alfe Over a year ago

You might want to look at stackoverflow.com/questions/9994295/… for more information on this.

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