Running a python script with arguments that contain space from another python script

Question

I am trying to run a python script from another python script but i am getting blocked because there is a space in the passed argument. The script I am trying to run is ran from the command terminal with the name and the arguments as such

>>>Duplicate_Checki.py "Google Control Center" "7.5 Hardening"

In the script which i try to call the first script the code looks like this:

def run_duplicate_check(self):
    os.system("python Duplicate_Checki.py Google Control Center 7.5 Hardening")

I get the following error

Duplicate_Checki.py: error: unrecognized arguments: Center 7.5 Hardening

Also tried os.system("python Duplicate_Checki.py {} {}".format("Google Control Center" ,"7.5 Hardening")) with the same error

I have also tried

os.system(python Duplicate_Checki.py "Google Control Center" "7.5 Hardening")

but i get invalid syntax

You'll need to escape the spaces: os.system('python Duplicate_Checki.py "Google\ Control\ Center 7.5\ Hardening"') — inspectorG4dget
– inspectorG4dget, Commented Jun 20, 2017 at 21:23
Look at subprocess.run. It doesn't do any splitting on spaces. — Artyer
– Artyer, Commented Jun 20, 2017 at 21:24

glegoux · Accepted Answer · 2017-06-20 21:29:26Z

2

script.py:

import sys

if __name__ == '__main__':
    args = sys.argv[1:]
    print(args[0])
    print(args[1])

runner.py:

from subprocess import call

call(["python3", "script.py", "Google Control Center", "7.5 Hardening"])

Execution python3 runner.py, output:

Google Control Center
7.5 Hardening

See https://docs.python.org/3/library/subprocess.html

#subprocess.run, #subprocess.check_output, #subprocess.call

answered Jun 20, 2017 at 21:29

glegoux

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1 Comment

j.doe Over a year ago

I'am running the version Python 2.7, so i used call(["Duplicate_Checki.py", "Google Control Center", "7.5 Hardening"], shell = True)

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