Redirect to a URL which contains a 'variable part' in Flask (Python)

Question

I'm trying to redirect to a URL in Flask. The target URL that I'm trying to redirect to has a variable like this /dashboard/<username> which has a view as follows,

@app.route('/dashboard/<username>')
def dashboard(username):
    return render_template('dashboard.html', username=username)

How do I redirect to this URL using the Flask's redirect() & url_for() functions. I have tried this,

return redirect(url_for("index"))

which works fine as index is an URL without any variable part (/index) in my application. But, how do I do it for URLs which have variable paths?

Thanks

Makoto · Accepted Answer · 2013-05-02 18:50:55Z

16

You will want to create your URL with url_for by giving it the name of your URL, the keyword arg, and value for your URL parameter in the following manner:

return redirect(url_for('dashboard', username='foo'))

edited May 2, 2013 at 18:50

Makoto

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answered Apr 18, 2013 at 11:39

williamsbdev

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Comments

lukkaempf · Accepted Answer · 2021-06-03 15:40:07Z

0

The point '.dashboard' is important

return redirect(url_for('.dashboard', username='foo'))

edited Jun 3, 2021 at 15:40

answered Jun 2, 2021 at 12:22

lukkaempf

11 bronze badge

1 Comment

Shivam Roy Over a year ago

Your answer is the same as the accepted answer.

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