Flask redirect to url and pass query strings

Question

I have a view that is defined like such:

@views.route('/issues')
def show_view():
    action = request.args.get('action')
method = getattr(process_routes, action)
return method(request.args)

in my process_routes module, I would like to call this method, and pass query string values. I have the following code:

return redirect(url_for('views.show_view', action='create_or_update_success'))

I have a function in process_routes named create_or_update_success

I am getting

BuildError: ('views.show_view', {'action': 'create_or_update_success'}, None)

views is a blueprint. I can successfully call

/issues?action=create_or_update_success

In my browser.

What am I doing wrong?

Apparently url_for() cannot find the views.show_view registration. Are you sure your views Blueprint uses the name views when registered with your Flask object? — Martijn Pieters
– Martijn Pieters, Commented Aug 17, 2015 at 19:24
@MartijnPieters: I am sure that is the case. I have views = Blueprint(__name__, __name__). The app object is named app — Mark
– Mark, Commented Aug 17, 2015 at 19:31
__name__ is the name of the current module, so your Blueprint object is probably not named views. — Martijn Pieters
– Martijn Pieters, Commented Aug 17, 2015 at 19:38
I suspect that views.py is a module in a package, in which case __name__ will contain the full path. Don't use __name__ as the first argument, give it a string literal instead so you can be sure of its value. — Martijn Pieters
– Martijn Pieters, Commented Aug 17, 2015 at 20:09

Martijn Pieters · Accepted Answer · 2015-08-17 20:15:46Z

1

The first part, views., has to reflect the first argument you give to your Blueprint() object exactly.

Don't be tempted to set that first argument to __name__, as that is likely to contain the full path of the module when inside a package. In your case I suspect that to be some_package.views rather than just views.

Use a string literal for the Blueprint() first argument instead:

views_blueprint = Blueprint('views', __name__)

so you can refer to url_for('views.show_view') without getting build errors.

answered Aug 17, 2015 at 20:15

Martijn Pieters

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