How redirect with args for view function without query string on Flask?

Question

I want to redirect users to same path but with different arguments.

Here's my code:

@app.route('/foo')
def foo(args1=None, args2=None):
    return render_template('foo.html', args1=args1, args2=args2)

@app.route('/bar')
def redirect_to_foo():
    return redirect(url_for('foo', args1='something'))

But when I see url path, that shows /foo?arg1=something... .
How redirect with args but without query string?
Is there any way to do this?

See related programmers.stackexchange.com/questions/99894/…. HTML has no POST redirect. If you will implement it with Status-Code 307 the user will get a prompt. Another way would be to save arguments in a session before sending 301-redirect code. — wenzul
– wenzul, Commented Aug 21, 2015 at 6:47

Community · Accepted Answer · 2017-05-23 12:09:30Z

1

In HTTP 1.1, there actually is a status code (307) which indicates that the request should be repeated using the same method and post data. Try to use HTTP status code 307 Internal Redirect instead of 302. For flask there is a parameter code.

@app.route('/bar', methods=['POST'])
def redirect_to_foo():
    return redirect(url_for('foo', args1='something'), code=307)

Source: Redirecting to URL in Flask

And as a background also have a look in my comments in OP.

Hint: Maybe it's not the right I answer. I didn't understand why you want to redirect with different arguments. Sending back "different arguments" as a HTTP payload beside an redirect header is AFAIK (except for GET/"in query string") not possible. If you really have to do it, think about the structure.

edited May 23, 2017 at 12:09

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answered Aug 21, 2015 at 6:53

wenzul

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2 Comments

Jony cruse Over a year ago

Thanks. I tried 307 redirect but the url redirected is still /foo?args=something .

wenzul Over a year ago

@Jonycruse It will work. Your initial request also have to be a POST request.

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