redirecting with url_for to a path with query params in flask

Question

So let's say I have a template with a couple of links, the links will be like this:

<a class='btn btn-primary' href='/?chart=new_chart&chart=other_chart'>View Summary</a>

However, most of the times when I have done links or included resources, I have used the following syntax:

<script src="{{ url_for('static', filename='some_silly_js') }}"></script>

is it possible to do a url_for with query parameters? Something like:

<a href="{{ url_for('stats', query_params={chart: [new_chart, other_chart]}) }}>View More</a>

Martijn Pieters · Accepted Answer · 2014-04-17 22:08:39Z

60

Any extra keyword parameters passed to url_for() which are not supported by the route are automatically added as query parameters.

For repeated values, pass in a list:

<a href="{{ url_for('stats', chart=[new_chart, other_chart]) }}>View More</a>

Flask will then:

Demo, with 'stats' being the endpoint name for /:

>>> url_for('stats', chart=['foo', 'bar'])
'/?chart=foo&chart=bar'

answered Apr 17, 2014 at 22:00

Martijn Pieters

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Comments

Gopal Singh Sirvi · Accepted Answer · 2021-05-06 09:55:20Z

2

As per the documentation:

Variable arguments that are unknown to the target endpoint are appended to the generated URL as query arguments.

I have tried this and it works as per the documentation

redirect(url_for('face_id_detail', faceid=faceid, name=faceidtag))

Note: faceid is the parameter in the method && name is not in the method parameters so it is appending to querystring.

The method signature for face_id_detail is:

@app.route('/faceids/<faceid>')
def face_id_detail(faceid):
    # the method code

answered May 6, 2021 at 9:55

Gopal Singh Sirvi

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