Is it possible to use "if" in arrayfun like the following in Octave?
a = [ 1 2; 3 4];
arrayfun(@(x) if x>=2 1 else 0 end, a)
And Octave complains:
>>> arrayfun(@(x) if x>=2 1 else 0 end, a)
^
Is if clause allowed in arrayfun?
In Octave you can't use if/else statements in an inline or anonymous function in the normal way. You can define your function in it's own file or as a subfunction like this:
function a = testIf(x)
if x>=2
a = 1;
else
a = 0;
end
end
and call arrayfun like this:
arrayfun(@testIf,a)
ans =
0 1
1 1
Or you can use this work around with an inline function:
iif = @(varargin) varargin{2 * find([varargin{1:2:end}], 1, ...
'first')}();
arrayfun(iif, a >= 2, 1, true, 0)
ans =
0 1
1 1
There's more information here.
In MATLAB you don't need an if statement for the problem that you describe. In fact it is really simple to use arrayfun:
arrayfun(@(x) x>=2, a)
My guess is that it works in Octave as well.
Note that you don't actually need arrayfun in this case at all:
x>=2
Should do the trick here.
