I have a string as follows:
char myString[] = "Amazing String";
I want to loop over the string and print characters as follows:
int i = 0;
for (i = 0;i < sizeof(myString);i++){
printf("%s\n", myString[i]);
}
But for some reason i get integer values instead of the character itself.
Sorry if this is a completely stupid question but i cant see what i am doing wrong.
You want to use strlen() instead for the length of a string and you want to print characters (%c):
int i = 0;
for (i = 0;i < strlen(myString);i++){ // to get a string's length, use strlen
printf("%c\n", myString[i]); // to print a single character, use %c
}
Why use strlen() over sizeof()? Well, in this particular instance, it won't make a difference; however strlen() is for giving you the number of printable characters in a string whereas sizeof will return the size of your array (printable characters + 1 for null terminator).
int len1 = sizeof(myString); // 15
int len2 = strlen(myString); // 14
A) you won't see that printed so it doesn’t help
B) if you get in the habit of using sizeof on strings you might use it within a function you pass your array to (in which case the array will decay to a pointer) and then you'll get back the size of a char * not the number of characters at all. Same applies within the same function if you had done char *myString = "Amazing String";
You're using the "%s" symbol for strings when you should be using "%c" for single characters:
printf("%c\n", myString[i]);
// ^^
int i = 0;
for (i = 0;i < sizeof(myString);i++){
printf("%c\n", myString[i]);
}
%c instead of %s and sizeof() is not a good choice. try strlen(myString)
sizeoflike that.