Get the number string from a char variable and re-assign it to a integer variable

Question

Here i have a char type variable which holds a number value as string say 21,I want to assign 21 to a integer variable.I did the following thing but it prints -12.why it is printing -12 and how i can get 21 in my int variable?

#include<stdio.h>

int main(){
char character = "21";
int x = (int)character - '0';
printf("%d",x);
}

It is invalid code to put char character = "21";. The data is a string literal which should be assigned to a char array like char character[] = "21"; — Weather Vane
– Weather Vane, Commented Oct 21, 2016 at 19:20
Also note that char *character = "21"; is a valid alternative. — byxor
– byxor, Commented Oct 21, 2016 at 19:22
With the code int x = (int)character - '0'; this would work, but only for a single digit such as char character = '7'; — Weather Vane
– Weather Vane, Commented Oct 21, 2016 at 19:23

MayurK · Accepted Answer · 2016-10-21 19:19:42Z

3

Use "sscanf".

int main(){
char *character = "21";
int x = 0;

sscanf(character, "%d", &x);
printf("%d",x);
}

answered Oct 21, 2016 at 19:19

MayurK

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EricS · Accepted Answer · 2016-10-21 19:20:06Z

0

The proper way to convert from a string to an integer is to use the atoi() or sscanf() functions.

answered Oct 21, 2016 at 19:20

EricS

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