Pass array to shader

Question

I create my array this.kernel: it hast 48 elements and I want to pass it to my fragment shader.

When i call

 gl.uniform3fv(gl.getUniformLocation(this.program, "kernel"), 16, this.kernel);

kernel is defined in my shader:

uniform vec3 kernel[16];

I get an error for not enough arguments. I already looked up the specification etc, but don't find my problem -.-

void glUniform3fv(  GLint  location, GLsizei  count, const GLfloat * value);

Thanks for help

€: I converted this.kernel to a float32array but I still have this error.

€2: error in Chrome: not enough arguments

in Firefox: NS_ERROR_XPC_BAD_CONVERT_JS: Could not convert JavaScript argument

Mortennobel · Accepted Answer · 2013-06-09 12:29:14Z

3

Your this.kernel needs to be a Float32Array of length 48 (=3*16). You cannot use an array of vec3s.

Also the count is not used in WebGL. The function is (from WebGL Specification)

void uniform3fv(WebGLUniformLocation? location, Float32Array v);

Example usage:

gl.uniform3fv(gl.getUniformLocation(shaderProgram, "colors"), new Float32Array([0,1,2,3,4,5]));

See a complete example here: http://jsfiddle.net/mortennobel/URvtx/

edited Jun 9, 2013 at 12:29

answered Jun 8, 2013 at 20:04

Mortennobel

3,5016 gold badges31 silver badges48 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Pris0n Over a year ago

AH ok. I changed my array this.kernel to this.kernel = new Float32Array(this.kernel); The length is exactly 48 long. Just to be clear I meant the kernel in my shader is a vec3 Still getting the error not enough arguments.

Pris0n Over a year ago

Thank you. I experimented so much but it seems I forgot this variation.

Collectives™ on Stack Overflow

Pass array to shader

1 Answer 1

2 Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

2 Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related