Powershell module and invoking files

Question

I have a script based powershell module (.psm1) and I have it imported into my main script. This module however needs to call a batch file that is located inside its same directory but apparently it is unable to see it. Currently the function in question looks like this:

function MyFunction
{
    & .\myBatch.bat $param1 $param2
}

How can I make the function see the batch file?

Community · Accepted Answer · 2017-05-23 11:56:32Z

3

. is the current working directory, not the directory in which the module resides. The latter can be determined via the MyInvocation variable. Change your function to this:

function MyFunction {
  $Invocation = (Get-Variable MyInvocation -Scope 1).Value
  $dir = Split-Path $Invocation.MyCommand.Path
  $cmd = Join-Path $dir "myBatch.bat"
  & $cmd $param1 $param2
}

edited May 23, 2017 at 11:56

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answered Jul 11, 2013 at 15:46

Ansgar Wiechers

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4 Comments

Adi Inbar Over a year ago

Why are you accessing MyInvocation in the parent scope? Wouldn't it be defined in the local (script) scope? I tested this and it doesn't work - the .Path property is null. I'd just access $MyInvocation directly from the script with no scope modifiers.

Ansgar Wiechers Over a year ago

The function is defined in a module, and he needs the path of that module, not of the script importing the module.

Adi Inbar Over a year ago

I suggest a more compact version: & (Join-Path (Split-Path $script:MyInvocation.MyCommand.Path) 'myBatch.bat') $param1 $param2

Ansgar Wiechers Over a year ago

@AdiInbar My answer has separate statements, because that way it's clearer what each step does. But thanks for the suggestion.

Adi Inbar · Accepted Answer · 2013-07-11 16:52:53Z

1

Try this:

function MyFunction {
  & (Join-Path (Split-Path $MyInvocation.MyCommand.Path) 'myBatch.bat') $param1 $param2
}

answered Jul 11, 2013 at 16:52

Adi Inbar

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