redirect sending variables symfony

Question

I'm new to Symfony (working on my first project!) and I want to send the user back to the login page with an error saying "You aren't logged in" in case they aren't.

Is there any way to run something so that it changes the user's URL from /secured to /login and send data exactly like:

return $this->render('radloginBundle:Default:login.html.twig',array('errors'=>'You aren\'t logged in'));

So that in the login.html.twig, I have:

{% if errors is defined %}
<div class="red">{{errors}}</div>
{% endif %}

And it will show the user the error message?

I've heard of a method where you can do this:

return $this->redirect($this->generateUrl('radlogin_login',array('errors'=>'You aren\'t logged in')));

But the user's url turns into:

http://.../app_dev.php/login?errors=You+aren't+logged+in

instead of:

http://.../app_dev.php/login

Set a flash message and throw a AccessDeniedException

Emii Khaos
– Emii Khaos

2013-07-12 23:19:54 +00:00
Commented Jul 12, 2013 at 23:19 — Emii Khaos
– Emii Khaos, Commented Jul 12, 2013 at 23:19

Thomas Potaire · Accepted Answer · 2013-07-14 00:53:05Z

1

You can use the flash bag of the session service to pass values through a single request (a redirection really).

The chapter about flash messages can be found in the Symfony documentation.

If the doc isn't enough, here is a code sample:

public function updateAction()
{
    // if the method returns null, the user isn't logged in
    if ($this->getUser() === null) {
        $this->get('session')->getFlashBag()->add(
            'errors', // this is a key
            'You are not logged in' // this is a value to add to key
        );

        // this will redirect to the login page if the user isn't logged in
        throw new \Symfony\Component\Security\Core\Exception\AccessDeniedException();
    }
}

Then you can use the method explained in the documentation to show the errors.

answered Jul 14, 2013 at 0:53

Thomas Potaire

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