Looping an array then display the Odd and Even values in each arrays

Question

So I have this problem.

Input # of rooms: 4
room1:6
room2:4
room3:7
room4:3

(if I type 5 in "Input # of rooms" there would also be room5)

Odd: 7 3
Even: 6 4

I have to display the odd and even numbers, so I came up with this code:

System.out.print("Input # of rooms: ");
int rms=Integer.parseInt(io.readLine());

int[] array=new int[rms];
int a=0;
int b=1;


do {

    System.out.print("room "+b+":");
    array[a] = Integer.parseInt(io.readLine());
    a++;
    b++;

} while (a<rms);

I don't know how to display which are Odd numbers and which are Even numbers?

I take it you're using Java?

Paul
– Paul

2013-07-19 02:21:59 +00:00
Commented Jul 19, 2013 at 2:21 — Paul
– Paul, Commented Jul 19, 2013 at 2:21

null · Accepted Answer · 2013-07-19 02:24:28Z

5

you want to find the remainder or modulus when the param is divided by 2.

3 % 2 = 1 so odd 4 % 2 = 2 so even

if(param % 2 == 1){
  Print odd number
}else{
  Print even number
}

Should get you started

answered Jul 19, 2013 at 2:24

null

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Comments

Makoto · Accepted Answer · 2013-07-19 02:26:42Z

The use of the modulo operator (%) will be invaluable here - it performs integer division and returns the remainder of the quotient - kind of like short division.

The rules for determining the type of number are simple:

If the number is even, it is divisible by 2.
Otherwise, it is odd.

As for the printing part: I would recommend accumulating the values in two separate StringBuffers or Strings if you prefer, adding a space between when we get another of the type of value we want. Then, we can print it out pretty after we're done iterating through the array.

One last thing - you should only need one loop - preferably a for loop, since you know exactly how many elements you're going to iterate over. You can use the above rules for modulus to determine which number gets appended to which variable.

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