Putting user created variables inside of an array

Question

I want to put what the use puts in for x to be stored in the yourNumbers array, how would I do that? Edit: How would I clean up the println parts at the bottom, using loops.

import java.util.Scanner; 
 public class array {
public class SS_Un8As1 {
public static void main(String[] args) {
    Scanner scan = new Scanner(System.in);
    int[] yourNumbers = new int[10];
    for (int counter=0; counter < yourNumbers.length; counter++){
        System.out.print("Enter your number: ");
        yourNumbers[counter] = scan.nextInt();
     }         
   System.out.println("Original numbers: " + yourNumbers[0] + "," + yourNumbers[1] + "," + yourNumbers[2] + "," + yourNumbers[3] + "," + yourNumbers[4] + "," + yourNumbers[5] + "," + yourNumbers[6] + "," + yourNumbers[7] + "," + yourNumbers[8] + "," + yourNumbers[9]);
   System.out.println("Original numbers multiplied by five: " + yourNumbers[0]*5 + "," + yourNumbers[1]*5 + "," + yourNumbers[2]*5 + "," + yourNumbers[3]*5 + "," + yourNumbers[4]*5 + "," + yourNumbers[5]*5 + "," + yourNumbers[6]*5 + "," + yourNumbers[7]*5 + "," + yourNumbers[8]*5 + "," + yourNumbers[9]*5);
   System.out.println("Original numbers minus the next number: " + (yourNumbers[0]-yourNumbers[1]) + "," + (yourNumbers[1]-yourNumbers[2]) + "," + (yourNumbers[2]-yourNumbers[3]) + "," + (yourNumbers[3]-yourNumbers[4]) + "," + (yourNumbers[4]-yourNumbers[5]) + "," + (yourNumbers[5]-yourNumbers[6]) + "," + (yourNumbers[6]-yourNumbers[7]) + "," + (yourNumbers[7]-yourNumbers[8]) + "," + (yourNumbers[8]-yourNumbers[9]) + "," + (yourNumbers[9]-yourNumbers[0]));
}

}

@morpheus05 even better, he should store the length in a variable and use that — Jordan
– Jordan, Commented Jul 24, 2013 at 20:35
the array has a .length field which would perform this task. — morpheus05
– morpheus05, Commented Jul 24, 2013 at 20:48
How would I clean up the bottom part of my code, my teachers says to use loops but I have no idea what she means by that. — Bill
– Bill, Commented Jul 24, 2013 at 21:26

Óscar López · Accepted Answer · 2013-07-24 20:31:48Z

3

Like this:

yourNumbers[counter] = x;

The above code is stating: store the value of x in the array yourNumbers in the index (position) counter. Because counter is the iteration variable of a for loop, each time the loop advances the counter the next value of x will be stored in the next available position in the array.

You must make sure that the length of the array is the same as the value of counter. In your code, do this:

int[] yourNumbers = new int[10];

Why? because counter goes from 0 to 9, so the array must be of length 10.

answered Jul 24, 2013 at 20:31

Óscar López

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3 Comments

Bill Over a year ago

What does the [i] stand for?

morpheus05 Over a year ago

he ment counter. Its the index variable of the array.

Henry Keiter Over a year ago

Even better, for (int counter=0; counter < yourNumbers.length; counter++), to allow changing the length of the array in just one place.

Ankit · Accepted Answer · 2013-07-24 20:33:21Z

2

replace this

int x = scan.nextInt();

with

yourNumbers[counter] = scan.nextInt();

also, the condition should be counter<9, or better counter<yourNumbers.length

answered Jul 24, 2013 at 20:33

Ankit

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Comments

Undefined · Accepted Answer · 2013-07-24 20:33:24Z

1

Simply pass the input into the next element of the array, while inside the for loop:

yourNumbers[counter] = x;

I should also point out, however, that you should validate that your input is actually an integer before assigning x the value. If the value isn't an integer, your program will crash.

answered Jul 24, 2013 at 20:33

Undefined

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