I have a large numbers of variables. What is the most correct way to calculate the sum. Below is the static way. .What if the numbers will increase to N times?
function abc(a,b,c,d){
alert(a+b+c+d);
}
abc(2,3,4,5);
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8Why don't you use an array instead of a large number of variables? Will make adding up easy.Patrick Kostjens– Patrick Kostjens2013-07-27 19:47:54 +00:00Commented Jul 27, 2013 at 19:47
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1Where are the numbers coming from? User input?comp– comp2013-07-27 19:49:07 +00:00Commented Jul 27, 2013 at 19:49
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4 Answers
function abc(){
return Array.prototype.reduce.call(arguments, function(a,b) {
return a + b;
}, 0);
}
We can reduce the verbosity by binding .reduce as the this value of .call.
var reduce = Function.call.bind([].reduce);
Then it's just:
function abc(){
return reduce(arguments, function(a,b) {
return a + b;
}, 0);
}
Comments
You could use arguments
function abc(){
var total = 0;
for( var i = 0; i < arguments.length; i++) {
total += arguments[i];
}
alert(total);
}
abc(1, 2, 3, 4, 5, 6, 7);
Demo
OR
function abc( args ){
var total = 0;
for( var i = 0; i < args.length; i++) {
total += args[i];
}
alert(total);
}
abc([1, 2, 3, 4, 5, 6, 7]);
Demo
The best way would be to use the latter.
4 Comments
Jeff Bowman
The
arguments array isn't deprecated in strict mode, but strict mode does change it and remove some behavior.
John Dvorak
arguments haven't been deprecated or removed. arguments.caller was, but it was replaced with arguments.callee.callerTo accept a limitless number of arguments automatically, use the arguments property.
function sum() { // javascript functions can accept more arguments than specified
var total = 0;
for (var i = 0; i < arguments.length; i++) {
total += arguments[i];
}
return total;
}
Bear in mind that this might not actually be much shorter or more-readable than just calling "a + b + c + d" in your original code.
Comments
Here is a shorter version using the Array.reduce() command.
function abc() {
alert([].reduce.call(arguments, function(a, b) { return a + b; }));
}
abc(2,3,4,5);
1 Comment
Dmitry S.
Crazy Train posted the same solution while I was testing it.